Sinusoidal AC current reference \(i(t)=I_m\sin(2\pi f t)\) | Dashed line: current waveform · Solid line: instantaneous power waveform
Voltage amplitude \(V_m\) affects power amplitude | Average power of pure energy storage components is zero
Increasing voltage makes power peak significantly higher than current amplitude for easier observation
Frequency changes inductive/capacitive reactance → affects current amplitude and power peak
Inductor current lags voltage by 90°, power \(p_L(t)=\frac{V_m^2}{2\omega L}\sin(2\omega t)\)
Capacitor current leads voltage by 90°, power \(p_C(t)= -\frac{V_m^2 \omega C}{2}\sin(2\omega t)\)
Let \(i(t)=I_m\sin(\omega t)\), then inductor voltage \(v_L = L\frac{di}{dt}= \omega L I_m \cos(\omega t)\),
Instantaneous power \(p_L = \frac{\omega L I_m^2}{2}\sin(2\omega t)\).
Capacitor voltage \(v_C = \frac{1}{C}\int i\,dt = -\frac{I_m}{\omega C}\cos(\omega t)\),
Instantaneous power \(p_C = -\frac{I_m^2}{2\omega C}\sin(2\omega t)\).
Where \(I_m = V_m/(\omega L)\) (inductor) or \(I_m = V_m \omega C\) (capacitor).
• Current reference is a sine wave (red dashed), power waveform is a double-frequency sine.
• Inductor power \(p_L\) is always a positive sine half-cycle (absorb → release), capacitor power \(p_C\) is a negative sine.
• Increasing voltage \(V_m\) or decreasing frequency/reactance makes power peak clearly exceed current peak.
• Pure energy storage component average power = 0, reactive power \(Q = \pm \frac{V_m^2}{2X}\).