Apply the sinusoidal AC voltage \(v(t) = V_m \sin(2\pi f t)\) to \(R\), \(L\), and \(C\) components and compare their voltage-current phase relationships
Resistor current: milliamps (mA) | Inductor/Capacitor current: amperes (A)
Frequency affects inductive/capacitive reactance but does not change the theoretical phase difference (±90°)
Resistor voltage and current are in phase, current amplitude \(I_m = V_m / R\) (mA)
Current lags voltage by \(90^\circ\), amplitude \(I_m = V_m / (\omega L)\) (A)
Current leads voltage by \(90^\circ\), amplitude \(I_m = V_m \cdot \omega C\) (A)
• Resistor: \(u_R\) and \(i_R\) cross zero simultaneously, peaks occur at the same time.
• Inductor: current \(i_L\) zero-crossing lags voltage \(u_L\) by \(90^\circ\) (current is zero at voltage peak).
• Capacitor: current \(i_C\) zero-crossing leads voltage \(u_C\) by \(90^\circ\) (voltage is zero at current peak).
• Adjusting frequency \(f\), inductance \(L\), capacitance \(C\) changes current amplitude, but phase difference remains at theoretical value.
• Resistor current in mA, Inductor/Capacitor current in A, for easy amplitude comparison on the same coordinate system.
\(I_{Lm} = \frac{V_m}{2\pi f L}\ \text{(A)}\), \(I_{Cm} = V_m \cdot 2\pi f C\ \text{(A)}\).
Increase frequency \(f\) → inductor current decreases, capacitor current increases;
Increase \(L\) → inductor current decreases; Increase \(C\) → capacitor current increases.
Resistor current \(I_{Rm}= \frac{V_m}{R} \times 1000\ \text{mA}\), convert \(R\) from kΩ to Ω when calculating.